AMU Medical AMU Solved Paper-2011

  • question_answer
    Two wires A and B of equal masses and of the same metal are taken. The diameter of the wire A is half the diameter of the wire B. If the resistance of wire A be 24\[\Omega \], the resistance of B will be

    A)  3 \[\Omega \]                                  

    B)  1.5 \[\Omega \]

    C)  4.5 \[\Omega \]                              

    D)  6.0 \[\Omega \]

    Correct Answer: D

    Solution :

                     Resistance of a conductor is directly proportional to ifs length and inversely proportional to its area.                                 \[R\propto \frac{1}{A}\] \[\therefore \]  \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{A}_{2}}}{{{A}_{1}}}\]                                 \[\frac{{{R}_{A}}}{{{R}_{B}}}=\frac{\pi r_{B}^{2}}{\pi r_{A}^{2}}=\frac{r_{B}^{2}}{r_{A}^{2}}=\frac{{{(2{{r}_{B}})}^{2}}}{{{(2{{\pi }_{A}})}^{2}}}\]                                 \[\frac{{{R}_{A}}}{{{R}_{B}}}=\frac{{{(2{{r}_{B}})}^{2}}}{\left( \frac{2{{\pi }_{B}}^{2}}{2} \right)}=\frac{4r_{B}^{2}}{r_{B}^{2}}\]                                 \[\frac{24}{{{R}_{B}}}=\frac{4}{1}\]                                 \[{{R}_{B}}=6\,\,\Omega \]


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