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AMU Medical AMU Solved Paper-2011

  • question_answer
    A circular coil of 20 turns and radius 10 cm is placed in a uniform magnetic field of 0.10 T normal to the plane of the coil. If the current in the coil is 5.0 A, the total torque on the coil will be

    A)  zero                                     

    B)  0.314 J

    C)  3.14 J                                   

    D)  6.28 J

    Correct Answer: B

    Solution :

                     Area \[=\pi {{r}^{2}}=\pi \times 10\times 10\times {{10}^{-4}}{{m}^{2}}\] Torque \[\tau =NiBA\,\sin \theta \]                 \[=20\times 5\times 0.10\times \pi \times 10\times 10\times {{10}^{-4}}\]                 \[=3.14\,J\]


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