A) 225 N
B) 300 N
C) 450 N
D) 675 N
Correct Answer: D
Solution :
\[y=0.06\sin \left( \frac{2\pi }{3} \right)\cos (100\pi t)\] Comparing on standard equation \[y=2a\,\sin \frac{2\pi x}{\lambda }\cos \frac{2\pi vt}{\lambda }\] We will get frequency, \[n=\frac{v}{\lambda }=50\] Frequency of vibration \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] \[50=\frac{1}{2\times 1.5}\sqrt{\frac{T}{3\times {{10}^{-2}}}}\] \[50\times 50=\frac{1}{3\times 3}.\,\frac{T}{3\times {{10}^{-2}}}\] or \[T=50\times 50\times 3\times 3\times 3\times {{10}^{-2}}\] \[T=675\,\,N\]You need to login to perform this action.
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