A) \[20\text{ }mA,\text{ }0\]
B) \[20mA,4W\]
C) \[20\sqrt{2}\,mA,8W\]
D) \[20\sqrt{2}\,mA,4\sqrt{2}W\]
Correct Answer: C
Solution :
\[V=200\sqrt{2}\sin (100t)\] Current \[{{i}_{0}}={{V}_{0}}\omega C\] \[=200\sqrt{2}\times 100\times 1\times {{10}^{-6}}\] \[=20\sqrt{2}\,mA\] Power \[P={{V}_{0}}{{i}_{0}}\] \[=200\sqrt{2}\times 20\sqrt{2}\times {{10}^{-3}}\] = 8 W
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