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AMU Medical AMU Solved Paper-2011

  • question_answer
    When a telescope is in normal adjustment, the distance of the objective from the eyepiece is found to be 100 cm. If the magnifying power of the telescope, at normal adjustment, is 24, the focal lengths of the lenses are

    A)  96 cm, 4 cm                       

    B)  48 cm, 2 cm

    C)  50 cm, 50 cm                   

    D)  80 cm, 20 cm

    Correct Answer: A

    Solution :

                                    \[L={{f}_{o}}+{{f}_{e}}=100\] and                        \[m=\frac{{{f}_{o}}}{{{f}_{e}}}=24\] \[\because \]     \[{{f}_{o}}=24{{f}_{e}}\] \[\therefore \]  \[24{{f}_{e}}+{{f}_{e}}=100\]                                 \[{{f}_{e}}=4\]                   and        \[{{f}_{o}}=24\times 4=96\]


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