A) 0.1 V
B) 1.0 V
C) 5.0 V
D) 3.3 V
Correct Answer: D
Solution :
\[E=e{{V}_{0}}\] \[E=hv=e{{V}_{0}}\] Stopping potential, \[{{V}_{0}}=\frac{hv}{e}\] \[=\frac{6.6\times {{10}^{-34}}\times 8\times {{10}^{14}}}{1.6\times {{10}^{-19}}}=3.3\,V\]You need to login to perform this action.
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