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AMU Medical AMU Solved Paper-2011

  • question_answer
    Consider the following reaction \[_{1}^{1}H+_{1}^{3}H+_{1}^{2}H\] The atomic masses are given as \[m(_{1}^{1}H)=1.007825\,u\] \[m(_{1}^{2}H)=2.014104\,u\] \[m(_{1}^{3}H)=3.016049\,u\] The Q-value of the above reaction will be

    A)  - 4.03 MeV                        

    B)  -2.01 MeV

    C)   2.01 MeV                          

    D)  4.03 MeV

    Correct Answer: D

    Solution :

                                    \[\Delta M=4.028204-4.023874\]                 \[=4.33\times {{10}^{-3}}u\] or            \[\Delta M=4.33\times {{10}^{-3}}\times 931\]                 = 4.03 MeV


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