A) \[A{{B}_{4}}\] type
B) \[A{{B}_{4}}\] E type
C) \[A{{B}_{4}}{{E}_{2}}\] type
D) None of these
Correct Answer: B
Solution :
\[S{{F}_{4}}\] molecule can be classified as \[A{{B}_{4}}E\] type. It has four bonding pairs electron and one lone pairs electron. The shape of \[S{{F}_{4}}\] is see saw.
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