AMU Medical AMU Solved Paper-2011

  • question_answer
    For the reaction, \[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g)\] equilibrium constant can be given

    A)  \[{{K}_{p}}{{K}_{c}}{{[RT]}^{-2}}\]          

    B)  \[{{K}_{p}}{{K}_{c}}{{[RT]}^{2}}\]

    C)  \[{{K}_{p}}{{K}_{c}}{{[RT]}^{{}}}\]                           

    D)  \[{{K}_{p}}{{K}_{c}}{{[nRT]}^{{}}}\]

    Correct Answer: A

    Solution :

                                                    \[{{K}_{p}}={{K}_{c}}={{[RT]}^{\Delta n}}\] where. \[\Delta n={{({{n}_{p}}-{{n}_{r}})}_{gaseous}}\]                 \[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g)\]                 \[\Delta n=2-4=-2\] \[\therefore \]  \[{{K}_{p}}={{K}_{c}}{{[RT]}^{-2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner