AMU Medical AMU Solved Paper-2011

  • question_answer
    \[{{E}^{o}}\] cell of a galvanic cell is 1.1 V. Standard free energy change can be given as

    A)  - 212.27 kJ \[mo{{l}^{-1}}\]         

    B)  - 212.27 J \[mo{{l}^{-1}}\]

    C)  + 212.27kJ \[mo{{l}^{-1}}\]         

    D)  + 212.27V

    Correct Answer: A

    Solution :

                     For a glavanic cell                 \[Zn+C{{u}^{2+}}\xrightarrow{{}}Cu+Z{{n}^{2+}}\]                 \[\Delta {{G}^{o}}=-nF{{E}^{o}}\] \[n=2,\,{{E}^{o}}=1.1\,V,F=96500\,\,C\,mo{{l}^{-1}}\] \[\Delta {{G}^{o}}=-2\times 96500\times 1.1\]                 \[=-212300\,\,J\,mo{{l}^{-1}}\]                 \[=-212.3\,\,J\,mo{{l}^{-1}}\]


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