A) \[{{K}_{2}}S{{O}_{4}}\]
B) \[CaC{{l}_{2}}\]
C) \[N{{a}_{3}}P{{O}_{4}}\]
D) \[AlC{{l}_{3}}\]
Correct Answer: D
Solution :
Coagulating power of an electrolyte is directly proportional to the valency of the active ions. \[A{{s}_{2}}{{S}_{3}}\] is a negative sol hence \[AlC{{l}_{3}}\] has maximum precipitating power for this.
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