A) \[{{N}_{3}}\]
B) \[N{{H}_{3}}\]
C) \[{{O}_{2}}\]
D) \[{{H}_{2}}\]
Correct Answer: A
Solution :
2-butanamine reacts with the solution of sodium nitrite in hydrochloric acid to form alcohol and evolve nitrogen. \[NaN{{O}_{2}}+HCl\xrightarrow{{}}NaCl+\underset{nitrous\text{ }acid}{\mathop{HN{{O}_{2}}}}\,\] \[C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ \underset{\begin{smallmatrix} 2-butanamine \\ \left( primary\text{ }amine \right) \end{smallmatrix}}{\mathop{N{{H}_{2}}}}\, \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}+HN{{O}_{2}}\xrightarrow{{}}\] \[C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \\ 2-bu\tan ol \end{smallmatrix}}{\mathop{CH-C}}\,{{H}_{3}}+{{N}_{2}}\uparrow +{{H}_{2}}O\]
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