A) Benzaldehyde
B) Methanal
C) 2,2-dimethyl propanal
D) Propanal
Correct Answer: D
Solution :
Aldehyde containing number. \[\alpha \]-H atom on reaction with concentrated alkali, undergoes disproportionation reaction. This is also known as Cannizzaros reaction. Since propanal contains \[\alpha \]-H atom hence it will not undergo disproportionation reaction. Propanal gives aldol condensation with dil. alkali. \[C{{H}_{3}}C{{H}_{2}}CHO+C{{H}_{3}}C{{H}_{2}}CHO\xrightarrow{Dil.\text{ }NaOH}\] \[C{{H}_{3}}-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,H-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,H-CHO\]
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