A) 0.5 ppm
B) 5.0 ppm
C) 15.0 ppm
D) 25.0 ppm
Correct Answer: D
Solution :
Through bio magnification the concentration of DDT is increased at successive trophic levels; say if it starts at 0.003 parts per million (ppm) in water, it can ultimately reach 25 parts per million (ppm) in fish eating birds. \[\underset{(DDT\,\,0.003\,ppm)}{\mathop{Water}}\,~\xrightarrow{{}}\text{ }\underset{(DDT\,\,0.05\,ppm)}{\mathop{Zooplankton}}\,\xrightarrow{{}}\]\[\underset{(DDT\,\,0.05\,\,ppm)}{\mathop{Small\text{ }Fish}}\,\xrightarrow{{}}\underset{(DDT\,\,2\,\,ppm)}{\mathop{Large\text{ }fish}}\,\xrightarrow{{}}\]\[\underset{(DDT\text{ }25\text{ }ppm)}{\mathop{Fish-eating\text{ }birds}}\,\]
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