(i) \[{{L}_{a}}={{L}_{p}}\] |
(ii) \[{{L}_{a}}=-{{L}_{p}}\] |
(iii) \[{{r}_{a}}\times {{L}_{a}}={{r}_{p}}\times {{L}_{p}}\] |
A) (i) only
B) (ii) only
C) (iii) only
D) (i) and (iii)
Correct Answer: A
Solution :
Using the law of conservation of angular momentum. Angular momentum of planet at p = Angular momentum of planet at a i.e., \[{{L}_{p}}={{L}_{a}}\] But \[{{r}_{a}}>{{r}_{p}}\] So, \[{{r}_{a}}\times {{L}_{a}}\times {{r}_{p}}\times {{L}_{p}}\] Hence, only option (a) is correct.You need to login to perform this action.
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