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AMU Medical AMU Solved Paper-2012

  • question_answer
    The work done by the gas liberated when 50 g of iron (molar mass 55.85 g \[mo{{l}^{-1}}\]) reacts with hydrochloric acid in an open beaker at \[{{25}^{o}}C\]

    A)  zero                                     

    B)  - 2.3 kJ

    C)  2.2kJ                                    

    D)  0.22kJ

    Correct Answer: B

    Solution :

    \[\underset{55.85\,\,g}{\mathop{Fe(s)}}\,+2HCl(aq)\xrightarrow{{}}FeC{{l}_{2}}(aq)+\underset{1\,\,mol}{\mathop{{{H}_{2}}(g)}}\,\]                 \[n=\frac{50}{55.85}=0.895\,\,mol\] \[W=-nRT-0.895\times 8.314\times {{10}^{-3}}\times 298\] \[=-2217.42\times {{10}^{-3}}=-2.2\,\,kJ\] The reaction mixture does - 2.2 kJ of work driving back the atmosphere.


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