A) 0
B) 0.20
C) 0.8
D) None of these
Correct Answer: D
Solution :
Given, \[i=10\,A,\,\,t=965\,\,s\] \[\therefore \] \[Q=i\,.\,\,t=9650\,\,C\] \[\underset{1\,\,mol}{\mathop{HCl}}\,\underset{1\,\,mol}{\mathop{{{H}^{+}}}}\,+\underset{1\,\,\,mol}{\mathop{C{{l}^{-}}}}\,\] Moles of \[HCl=1.0\times 1.0=1\,mol\] \[\because \,\,\,96500\,C\] charge deposits \[{{H}^{+}}=1\,mol\] \[\therefore \,\,9650\,\,C\] charge will deposite \[{{H}^{+}}=\frac{1\times 9650}{96500}\] \[=0.1\,\,mol\] \[[{{H}^{+}}]=0.1\,\,mol/L\] \[pH=-\log \,\,[{{H}^{+}}]=-\log \,\,(0.1)=1\]
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