A) 1 m/s
B) \[3\sqrt{2}\,m/s\]
C) \[5\sqrt{2}\,m/s\]
D) \[7\sqrt{2}\,m/s\]
Correct Answer: C
Solution :
Given, \[{{r}_{1}}(t)=3\,t\,i+4\,{{t}^{2}}j\] \[\therefore \] \[\frac{d{{r}_{1}}}{dt}=3i+8\,tj\] At \[t=1s\] \[{{v}_{1}}=\frac{d{{r}_{1}}}{dt}=3i+8j\] Again, \[{{r}_{2}}(t)=4\,{{t}^{2}}i+3tj\] \[\frac{d{{r}_{2}}}{dt}=8ti+3j\] At \[t=1s\] \[{{v}_{2}}=\frac{d{{r}_{2}}}{dt}=8i+3j\] Relative velocity \[={{v}_{1}}-{{v}_{2}}\] \[=-5i=5j\] \[=\sqrt{{{(5)}^{2}}+{{(5)}^{2}}}=5\sqrt{2}\,m/s\]You need to login to perform this action.
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