question_answer

Starting with the same initial conditions, an ideal gas expands from volume \[{{V}_{2}}\] in three different ways. The work done by the gas is \[{{W}_{1}}\]if the process purely isothermal, \[{{W}_{2}}\] if purely isobaric and \[{{W}_{3}}\] if purely adiabatic. Then

A)  \[{{W}_{2}}>{{W}_{1}}>{{W}_{3}}\]

B)  \[{{W}_{2}}>{{W}_{3}}>{{W}_{1}}\]

C)  \[{{W}_{1}}>{{W}_{2}}>{{W}_{3}}\]        

D)  \[{{W}_{1}}>{{W}_{3}}>{{W}_{2}}\]

Correct Answer: A

Solution :

                 Work done is equal to area under the curve on p-V diagram. This is largest for isobaric process and least for adiabatic expansion.