A) \[{{C}_{6}}{{H}_{5}}COOH+C{{H}_{3}}OH\xrightarrow{{{H}^{+}}}\]
B) \[{{C}_{6}}{{H}_{5}}COOCl+C{{H}_{3}}OH\xrightarrow{Pyridine}\]
C) \[{{C}_{6}}{{H}_{5}}COOH+C{{H}_{2}}{{N}_{2}}\xrightarrow{{}}\]
D) All of the above methods
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}COOH+C{{H}_{3}}OH\xrightarrow{{{H}^{+}}}\]\[\underset{methyl\text{ }benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COOHC{{H}_{3}}}}\,+{{H}_{2}}O\] (The reaction is known as Fischer - Sprier esterification reaction.) \[{{C}_{6}}{{H}_{5}}COCl+C{{H}_{3}}OH\xrightarrow{Pyridine}\]\[{{C}_{6}}{{H}_{5}}COOC{{H}_{3}}+HCl\] \[{{C}_{6}}{{H}_{5}}COOH+\,\,\underset{diazomethane}{\mathop{C{{H}_{2}}{{N}_{2}}}}\,\,\,\xrightarrow{{}}\]\[{{C}_{6}}{{H}_{5}}COOC{{H}_{3}}+{{N}_{2}}\] (Methyl easters can be prepared by treating carboxylic acid with ethereal solution of diazomethane. Hence, methyl benzoate can be prepared by all these above methods.You need to login to perform this action.
You will be redirected in
3 sec