A) 1308 N
B) 1090 N
C) 9100 N
D) 980 N
Correct Answer: C
Solution :
\[F=\frac{(m({{v}_{1}}-{{v}_{2}})}{t}\] \[=\frac{140\times {{10}^{-3}}(39+39)}{12\times {{10}^{-3}}}\] \[=\frac{1400\times 78}{12}\] = 9100 NYou need to login to perform this action.
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