A) trigonal bipyramidal
B) tetrahedral
C) square planar
D) distorted octahedral
Correct Answer: C
Solution :
In \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] , nickel is in +2 oxidation state and has electronic configuration 3d8. Orbitals of \[N{{i}^{2+}}\] ion \[ds{{p}^{2}}\] hybridised orbitals of \[N{{i}^{2+}}\] \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] low spin complex Therefore, the shape is square planar and the hybridisation involved is \[ds{{p}^{2}}\].You need to login to perform this action.
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