A) \[_{17}^{35}X\]
B) \[_{17}^{35}{{X}^{\Theta }}\]
C) \[_{17}^{37}X\]
D) \[_{17}^{37}{{X}^{\Theta }}\]
Correct Answer: D
Solution :
Suppose number of electrons in an ion = X Number of neutrons \[=x+\frac{11.1}{100}x=1.11x\] = 1.111 x Number of electrons in the neutral atom \[=x-1\] \[\therefore \] Number of protons \[=x-1\] Mass number = number of neutrons + number of protons \[\therefore 37=1.111x+x-1\]or \[2.111x=38\] or \[x=18\] Number of protons = atomic number \[=x-1\] = 18 - 1 = 17 Hence, the symbol of the ion will be \[_{17}^{37}{{X}^{-1}}\]
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