A) 0
B) 0.693 J/K
C) 5.76 J/K
D) None of these
Correct Answer: C
Solution :
Given that \[n=1\,mol\] \[{{p}_{1}}=1.0\times {{10}^{5}}Pa\] \[{{p}_{2}}=0.5\times {{10}^{5}}Pa\] Change in entropy of the gas \[=\frac{Q}{T}=\frac{W}{T}\] \[=\frac{nRT\log ({{p}_{1}}/{{p}_{2}})}{T}\] \[=nR\log ({{p}_{1}}/{{p}_{2}})\] \[=1\times 8.31\times 2.303\times 0.3010=5.76\,J/K\]You need to login to perform this action.
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