A) 0
B) \[\frac{q}{{{\varepsilon }_{0}}{{\pi }^{2}}{{r}^{2}}}\] perpendicular to the line OP and directed downward
C) \[\frac{q}{{{\varepsilon }_{0}}\pi {{r}^{2}}}\] perpendicular to the line OP and directed downward
D) \[\frac{q}{{{\varepsilon }_{0}}\pi {{r}^{2}}}\] along the axis OP
Correct Answer: B
Solution :
\[E=2\int{dE\cos \theta }\] \[E=\frac{2}{4\pi {{\varepsilon }_{0}}}\frac{2q}{\pi {{R}^{3}}}\int_{o}^{\pi /2}{\cos \theta \,d\theta }\] \[=\frac{q}{{{\pi }^{2}}{{\varepsilon }_{0}}{{R}^{2}}}\] \[=\frac{q}{{{\varepsilon }_{0}}{{\pi }^{2}}{{R}^{2}}}\] Perpendicular to the line OP and directed downward.You need to login to perform this action.
You will be redirected in
3 sec