A) \[\left| B \right|=\frac{{{\mu }_{0}}i}{8R}\] into the plane of the figure
B) \[\left| B \right|=\frac{{{\mu }_{0}}i}{8R}\] out of the plane of the figure
C) \[\left| B \right|=\frac{{{\mu }_{0}}i}{8\pi R}\] in to the plane of the figure
D) \[\left| B \right|=\frac{{{\mu }_{0}}i}{8\pi R}\] out of the plane of the figure
Correct Answer: C
Solution :
Magnetic field at C is \[B=\frac{1}{4}\] (due to whole circle) \[=\frac{1}{4}\left( \frac{{{\mu }_{0}}i}{2R} \right)=\frac{{{\mu }_{0}}i}{8R}\]You need to login to perform this action.
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