A) 0.12 A
B) 0.012 A
C) 0.045 A
D) 0.45 A
Correct Answer: C
Solution :
Number of cell \[(n)=3\] Number of row \[(m)=10\] Internal resistance \[=0.25\,\Omega \] \[R=10\,\Omega \] E = 0.15 V We know that, \[i=\frac{mnE}{nr+mR}\] \[\Rightarrow \] \[i=\frac{10\times 3\times 0.15}{3\times 0.25+10\times 10}\] \[\Rightarrow \] \[i=\frac{4.5}{0.75+100}\] \[\Rightarrow \] \[i=\frac{4.5}{100.75}\] \[\Rightarrow \] \[i=0.0446\] \[\Rightarrow \] \[i=0.045\,A\]You need to login to perform this action.
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