A) \[{{78}^{o}}C\]
B) \[{{88}^{o}}C\]
C) \[8.1\,C\]
D) None of the above
Correct Answer: B
Solution :
Energy loss per unit volume per cycle = area of hysteresis loop Energy loss per second per unit volume \[={{10}^{-2}}\times 50\,J\] Hence, heat produced in one minute \[Q={{10}^{-2}}\times 50\times 80\,J\] \[=\frac{30}{4.2}J\] Let \[\theta \] is rise in temperature, then \[8\times {{10}^{3}}\times 0.11\times {{10}^{-3}}\times \theta =\frac{30}{4.2}\] \[\theta =\frac{30}{4.2\times 8\times 0.11}\] \[\theta =8.1{{\,}^{o}}C\]You need to login to perform this action.
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