A) 205 MeV
B) 198 MeV
C) 123 MeV
D) 89 MeV
Correct Answer: A
Solution :
The reaction is, \[^{235}U+n{{\xrightarrow{{}}}^{140}}Ce+\,{{\,}^{94}}Zr+2n\] The mass lost in this reaction (mass defect) is \[\Delta m={{M}_{U}}+{{M}_{n}}-({{M}_{Ce}}+{{M}_{Zr}}+2{{M}_{n}})\] \[\Delta m=[235.02+1.0-(139.9+93.9+2)]\,u\] \[\Delta m=(236.02-235.8)\,u\] \[\Delta m=0.22\,u\] [\[\because \,1amu=931\,MeV\]] \[\therefore \] The disintegration energy \[\Delta E=0.22\times 931=204.82\,MeV\] \[\cong 205.00\,MeV\]You need to login to perform this action.
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