A) 2s
B) 1 s
C) 0.5 s
D) 0.25 s
Correct Answer: B
Solution :
According to the questions, \[O-x\frac{1}{2}g{{t}^{2}}\] \[{{t}^{2}}=\frac{2(10-x)}{g}\] \[{{t}^{2}}=\frac{2(10-x)}{10}=\frac{10-x}{5}\] and \[x=\frac{g}{2}.\,\,t\times t\] \[x=\frac{10}{2}{{t}^{2}}\] \[x=5\,{{t}^{2}}\] Putting the value of x in Eq. (i), we get \[{{t}^{2}}=\frac{10-x}{5}\] \[5{{t}^{2}}=10-x\] \[5{{t}^{2}}=10-5{{t}^{2}}\] \[10{{t}^{2}}=10\] \[t=1\,\,s\]You need to login to perform this action.
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