A) 11 g, 0 g
B) 1 g, 3 g
C) 14 g, 3 g
D) 11 g, 3 g
Correct Answer: C
Solution :
\[{{N}_{2}}\,\,\,\,\,+3{{H}_{2}}2N{{H}_{3}}\] 28 g 6g 34 g \[\because 34\,g\] \[N{{H}_{3}}\] was produced from \[=28\,g\,{{N}_{2}}\] \[\therefore \,17\,g\,\,\,N{{H}_{3}}\] will be produced from \[=\frac{28\times 17}{34}\] \[=14\,g\,{{N}_{2}}\] Similarly, 17 g of \[N{{H}_{3}}\] will be produced from \[=\frac{6\times 17}{34}\] \[=3\,\,g\,{{H}_{2}}\]You need to login to perform this action.
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