A) 310.2 K
B) 280.3 K
C) 420.5 K
D) 370.6 K
Correct Answer: A
Solution :
We know that, \[{{t}_{F}}={{32}^{o}}+\frac{9}{5}{{t}_{c}}\] [\[{{t}_{f}}={{98.6}^{o}}F\](given)] \[98.6=32=\frac{9}{5}{{t}_{c}}\] \[493=160+9{{t}_{c}}\] \[9{{t}_{c}}=493-160\] \[{{t}_{c}}=\frac{333}{9}\] \[{{t}_{c}}={{37}^{o}}C\] So, the temperature on a Kelvin scale is = 37 + 273 = 310 K or \[\approx 310.2\,K\]
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