AMU Medical AMU Solved Paper-2014

  • question_answer
    The mean free path of a gas molecule at STP is\[2.1\times {{10}^{-7}}m\]. Find the diameter of the molecule. (Boltzmann constant\[=1.4\times {{10}^{23}}J/K\])

    A) \[5.2\overset{\text{o}}{\mathop{\text{A}}}\,\]                                

    B) \[4.6\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C) \[3.5\overset{\text{o}}{\mathop{\text{A}}}\,\]

    D) \[2.1\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

                     The given,                 \[\lambda =2.1\times {{10}^{-7}}m\]                 \[{{K}_{B}}=1.4\times {{10}^{-23}}J/K\] For STP                 \[T={{0}^{o}}C+273=273\,K\]                 \[P=1\,atm=1.01\times {{10}^{5}}N/{{m}^{2}}\]                 \[d=?\]                 \[\lambda =\frac{{{K}_{B}}T}{\sqrt{2}\,\pi {{d}^{2}}\times P}\]                 \[=\frac{1.4\times {{10}^{-23}}\times 273}{1.41\times 3.14\times 2.1\times {{10}^{-7}}\times 1.01\times {{10}^{5}}}\]                 \[=\frac{382.2}{9.39}\times {{10}^{-21}}\]                 \[{{d}^{2}}=40.7\times {{10}^{-21}}=4.07\times {{10}^{-20}}\]                 \[d=\sqrt{4.07\times {{10}^{-20}}}=2.01\times {{10}^{-10}}\]                 \[d=2.01\,\overset{o}{\mathop{A}}\,\]                 \[d\cong 2.1\,\overset{o}{\mathop{A}}\,\]


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