AMU Medical AMU Solved Paper-2014

  • question_answer
    An observer moves towards a stationary source of sound with a velocity one-fifth the velocity of sound. What is the percentage change in the apparent frequency?

    A)  Increase by 0.5 %           

    B)  Decrease by 5 %

    C)  Increase by 20 %            

    D)  Increase by 50 %

    Correct Answer: C

    Solution :

                     Let initial speed of sound be v Therefore, frequency \[=\frac{v}{\lambda }\] (where, \[\lambda =\] wavelength)                                                 \[{{n}_{1}}=\frac{v}{\lambda }\]                                                                                ?. (i) According to the question,\[{{n}_{2}}=\frac{\frac{6v}{5}}{\lambda }\] (When, increase the velocity \[=v+\frac{v}{5}=\frac{6v}{5}\])                                                 \[{{n}_{2}}=\frac{6v}{5\lambda }\]                           ? (ii) The percentage (increase) \[=\frac{{{n}_{2}}-{{n}_{1}}}{{{n}_{1}}}\times 100\] \[=\frac{\frac{6}{5}\times \frac{v}{\lambda }-\frac{v}{\lambda }}{\frac{v}{\lambda }}\times 100=\frac{\left( \frac{6}{5}-1 \right)\frac{v}{\lambda }}{\frac{v}{\lambda }}\times 100\] \[=\frac{1}{5}\times 100=20%\] by increase


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