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AMU Medical AMU Solved Paper-2014

  • question_answer
    For a certain process, and \[\Delta H=178\,kJ\]\[\Delta S=160\,J/K\]. What is the minimum temperature at which the process is spontaneous (assuming that \[\Delta H\] and \[\Delta S\] do not vary with temperature)

    A)  2112.3 K             

    B)  136.7K

    C)  275.8 K                                

    D)  1112.5K

    Correct Answer: D

    Solution :

                     According to Gibbs-Helmholtz reaction,                 \[\Delta G=\Delta H-T\Delta S\] For a spontaneous reaction,                 \[\Delta G<0\] i.e.,        \[\Delta H-T\Delta S<0\] or            \[T>\frac{\Delta H}{\Delta S}\] or            \[T>\frac{178\times 1000}{160}\]                 \[T>1112.5\,K\] \[\therefore \] For spontaneous process, minimum temperature must be 1112.5 K.


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