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AMU Medical AMU Solved Paper-2014

  • question_answer
    28 g of \[{{N}_{2}}\] and 6 g of \[{{H}_{2}}\] were mixed. At equilibrium, 17 g \[N{{H}_{3}}\] was produced. The weights of \[{{N}_{2}}\] and \[{{H}_{2}}\] at equilibrium are respectively

    A)  11 g, 0 g              

    B)  1 g, 3 g

    C)  14 g, 3 g              

    D)  11 g, 3 g

    Correct Answer: C

    Solution :

                    \[{{N}_{2}}\,\,\,\,\,+3{{H}_{2}}2N{{H}_{3}}\] 28 g    6g                   34 g \[\because 34\,g\] \[N{{H}_{3}}\] was produced from \[=28\,g\,{{N}_{2}}\] \[\therefore \,17\,g\,\,\,N{{H}_{3}}\] will be produced from                 \[=\frac{28\times 17}{34}\]                 \[=14\,g\,{{N}_{2}}\] Similarly, 17 g of \[N{{H}_{3}}\] will be produced from                 \[=\frac{6\times 17}{34}\]                 \[=3\,\,g\,{{H}_{2}}\]


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