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AMU Medical AMU Solved Paper-2014

  • question_answer
    The value of the equilibrium constant for the reaction, \[{{N}_{2}}+2{{O}_{2}}2N{{O}_{2}}\] is 100. The equilibrium constant for the reaction \[N{{O}_{2}}\frac{1}{2}{{N}_{2}}+{{O}_{2}}\] will be

    A)  100                       

    B)  0.010  

    C)  0.10                      

    D)  1000

    Correct Answer: C

    Solution :

                     For the reaction,                 \[{{N}_{2}}+2{{O}_{2}}2N{{O}_{2}}\]                                 \[{{K}_{c}}=\frac{{{[N{{O}_{2}}]}^{2}}}{[{{N}_{2}}]\,\,{{[{{O}_{2}}]}^{2}}}=100\]  ?. (i) For the reaction, \[N{{O}_{2}}\frac{1}{2}{{N}_{2}}+{{O}_{2}}\]                 \[{{K}_{c}}=\frac{{{[{{N}_{2}}]}^{1/2}}[{{O}_{2}}]}{[N{{O}_{2}}]}\] or            \[{{({{K}_{c}})}^{2}}=\frac{[{{N}_{2}}]\,[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\]                 \[=\frac{1}{100}\]                            (from equation (i)] \[\therefore \]  \[K_{c}^{}=\sqrt{\frac{1}{100}}=\frac{1}{10}=0.10\]


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