A) \[C{{l}_{2}}{{O}_{7}}>S{{O}_{2}}>{{P}_{4}}{{O}_{10}}\]
B) \[C{{O}_{2}}>{{N}_{2}}{{O}_{5}}>S{{O}_{3}}\]
C) \[N{{a}_{2}}O>,MgO>A{{l}_{2}}{{O}_{3}}\]
D) \[{{K}_{2}}O>CaO>MgO\]
Correct Answer: A
Solution :
On passing from left to right in a period, acidic character of the normal oxides of the elements goes on increasing with increase in electronegativity. Thus, the correct order is \[{{P}_{4}}{{O}_{10}}<S{{O}_{2}}<C{{l}_{2}}{{O}_{7}}\]
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