A) Equilibrium shift to the right
B) Equilibrium shift to the left
C) No effect on equilibrium
D) Reaction stops
Correct Answer: A
Solution :
\[2\,\,S{{O}_{2}}(g)+{{O}_{2}}(g)2S{{O}_{3}}(g)\] Here, \[\Delta {{n}_{g}}=2-\,(2+1)=-1\] Therefore, according to Le-Chateliers principle, i the increase in pressure favours forward reaction, i.e., equilibrium will be shift to the right,You need to login to perform this action.
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