AMU Medical AMU Solved Paper-2015

  • question_answer
    The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum I Bo = 510 nT. What is the amplitude of the electric field?

    A)  140 \[N{{C}^{-1}}\]                        

    B)  153 \[N{{C}^{-1}}\]

    C)  163 \[N{{C}^{-1}}\]                        

    D)  133 \[N{{C}^{-1}}\]

    Correct Answer: B

    Solution :

                     In harmonic electromagnetic wave in vacuum Speed of light \[(c)=\frac{E}{B}\] \[\Rightarrow \]               \[E=(3\times {{10}^{8}})\times (510\times {{10}^{-9}}=153\,N{{C}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner