A) 0.18eV
B) 0.36eV
C) 0.74eV
D) 2.1eV
Correct Answer: B
Solution :
In case of photoelectric effect, \[e{{V}_{0}}=\frac{1}{2}m{{v}^{2}}\] [where, \[{{V}_{0}}\] is stopping potential] \[\Rightarrow \] Maximum kinetic energy of photoelectric is 0.36 eV.You need to login to perform this action.
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