A) \[2\,mg\,R\]
B) \[\,mg\,R\]
C) \[\frac{1}{2}\,mg\,R\]
D) \[\frac{1}{4}\,mg\,R\]
Correct Answer: C
Solution :
Change in \[PE=\frac{GMm}{R}-\frac{GMm}{(n+1)R}\] \[=\left( \frac{n}{n+1} \right)mgR\] where, n is integral multiple of R. Here value of-\[n=1\] \[\therefore \] Change in \[PE=\frac{mgR}{2}\]You need to login to perform this action.
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