A) 267 rev/min
B) 335 rev/min
C) 400 rev/min
D) 1150 rev/min
Correct Answer: A
Solution :
Angler momentum is conserved. \[{{I}_{b}}={{L}_{a}}\] \[{{l}_{1}}\,{{\omega }_{1}}+{{I}_{2}}{{\omega }_{2}}\] \[=I_{1}^{}\,\omega _{1}^{}+I_{2}^{}\,\omega _{2}^{}\] \[{{I}_{1}}\,{{\omega }_{1}}+0=(I+2I)\,{{\omega }_{f}}\] \[{{\omega }_{f}}=\frac{{{\omega }_{1}}}{3}=\frac{B\omega }{3}=267\] rev/minYou need to login to perform this action.
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