AMU Medical AMU Solved Paper-2015

  • question_answer
    The dimensional formula of Plancks constant, h is

    A)  \[[M{{L}^{2}}{{T}^{-1}}]\]                           

    B)  \[[M{{L}^{2}}{{T}^{-2}}]\]

    C)  \[[M{{L}^{0}}{{T}^{2}}]\]                             

    D)  \[[ML{{T}^{2}}]\]

    Correct Answer: A

    Solution :

                    From Energy equation,                 \[E=hv\] \[\Rightarrow \]               \[h=\frac{E}{v}\]                 \[=\frac{[M{{L}^{2}}{{T}^{-2}}}{[{{T}^{-1}}]}\]                 \[=[M{{L}^{2}}{{T}^{-1}}]\]


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