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AMU Medical AMU Solved Paper-2015

  • question_answer
    A battery of emf 10 V is connected to the network as shown in figure The potential difference between A and B is                

    A)                  -2V                                       

    B)                  2V

    C)  5V         

    D)  7V

    Correct Answer: C

    Solution :

                     Current in arm CD is       \[I=\frac{10}{1}=10A\] Current in both the arm get divided equally therefore potential difference across A and B is 5 V.


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