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AMU Medical AMU Solved Paper-2015

  • question_answer
    An average of emf 20 V is induced in an inductor when the current I in it is changed from 2.5 A in one direction to the same value in the opposite direction in 0.1 s. What is the self-inductance of the inductor?

    A)  Zero                                     

    B)  0.2 H

    C)  0.4H                                     

    D)  0.1H

    Correct Answer: C

    Solution :

                    emf induced in an inductor \[(e)=-L\frac{dI}{dt}\] Here,     \[e=20\,V\] \[\therefore \]  \[20=-L\frac{(-25-2.5)}{0.1}\] \[\Rightarrow \]               \[L=0.4\,H\]


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