AMU Medical AMU Solved Paper-2015

  • question_answer
    For the electrode \[{{H}^{+}}(aq)\,\left| {{H}_{2}}(g) \right.\], if pH is decreased by one unit at \[{{25}^{o}}C\], then the cell potential

    A)  decreases by 59.1 mV

    B)  increases by 59.1 mV

    C)  remains unchanged

    D)  becomes zero

    Correct Answer: B

    Solution :

                    From Nernst equation,  \[E=\frac{-RT\,{{\log }_{10}}\,pH}{F}\] This equation tells us that every decrease in pH of one unit, the potential of hydrogen electrode increases by\[\frac{RT{{\log }_{10}}}{F}(\approx 59.1\,mV\,at\,298\,K)\]. The Nernst equation has thus given us the pH dependence of any reaction involving hydrogen ions.


You need to login to perform this action.
You will be redirected in 3 sec spinner