AMU Medical AMU Solved Paper-2015

  • question_answer
    Enthalpy of \[C{{H}_{4}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}C{{H}_{3}}OH\], is negative. If enthalpies of combustion of \[C{{H}_{4}}\] and \[C{{H}_{3}}OH\] are x and y respectively, then which of the following relation is correct?

    A)  \[x>y\]                               

    B)  \[x<y\]

    C)  \[x=y\]                               

    D)  \[x\ge y\]

    Correct Answer: B

    Solution :

                    Enthalpy of combustion of \[C{{H}_{3}}OH\] is \[C{{H}_{3}}OH+\frac{3}{2}{{O}_{2}}\xrightarrow{{}}C{{O}_{2}}+2{{H}_{2}}O\], \[\Delta H_{e}^{o}=-726\,kJ/mol\] (Given, it is y) Enthalpy of combustion of \[C{{H}_{4}}\] is \[C{{H}_{4}}(g)+2{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)+2{{H}_{2}}O(l)\], \[\Delta H_{c}^{o}=-890\,kJ/mol\] (Given, it is x) Hence, \[x<y\]


You need to login to perform this action.
You will be redirected in 3 sec spinner