A) 2
B) 3
C) 4
D) 5
Correct Answer: C
Solution :
The number of optical isomers depends upon the number of asymmetric centres. In molecules which are not divisible into two equal halves and have n number of asymmetric C-atoms then, number of optically active forms \[={{2}^{n}}\]\[\underset{2,\text{ }3-dihydropentane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{\overset{*}{\mathop{C}}\,}}\,H-\overset{*}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,}}\,H-C{{H}_{2}}-C{{H}_{3}}}}\,\] Maximum number of optical isomers \[={{2}^{n}}\]\[={{2}^{2}}=4\]
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