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BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    Domain of the function \[f(x)=\frac{1}{\sqrt{x+2}}\]is:

    A)  R                                           

    B)  \[(-2,\infty )\]  

    C)         \[(2,\infty )\]   

    D)         \[(0,\infty )\]

    Correct Answer: B

    Solution :

    We have, \[f(x)=\frac{1}{\sqrt{x+2}}\] This function is defined only when \[x>-2\] \[\therefore \] Domain of the function is \[(-2,\infty ).\]


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